Question 635593
Graph hyperbola: y squared / 169 - x squared / 16 = 1
y^2/169-x^2/16=1
This is a hyperbola with vertical transverse axis with center at (0,0):
see graph below:

y=±(169+169x^2/16)^.5
{{{ graph( 300, 300, -10, 10, -30, 30,(169+169x^2/16)^.5,-(169+169x^2/16)^.5,13x/4, 13x/4,-13x/4) }}} 
slopes of asymptotes: a/b=13/4
equation of asymptotes:
y=13x/4
and 
-13x/4