Question 636615
k            4           k^2 -5k + 8
------- +   ------ +     ------------   
k + 1       1 - k        k^2 -1


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Rewrite: 
k             4         k^2 -5k + 8
-------  - ------    +  ------------  
k + 1       k - 1        k^2 -1

lcm = (k^2-1)
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Rewrite each fraction with the lcm as its denominator:
------
[k(k-1) -4(k+1) +k^2-5k+8]/[k^2-1]
------
[k^2-k-4k-4+k^2-5k+8]/[k^2-1]
------
[2k^2-10k+8]/[k^2-1]
----
= [2(k^2-5k+4)]/[k^2-1]
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= [2(k-4)(k-1)]/[(k+1)(k-1)]
-----
= [2(k-4)]/[k+1]
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Cheers,
Stan H.
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