Question 636519
 Select any two integers between -12 and +12 which will become solutions
 to a system of two equations.
:
Choose two integers, x =-5 and y=+10
:
1st equation
3(-5) + 2(10) = 
-15 + 20 = 5
3x + 2y = 5
:
2nd equation
6(-5) - 4(10) =
-30 - 40 = -70
6x - 4y = -70
:
Our two equations
3x + 2y = 5
6x - 4y = -70
:
Solve this using the addition method
Multiply the 1st equation by 2, add to the 2nd equation
6x + 4y = 10
6x - 4y = -70
----------------adding eliminates y, find x
12x + 0 = -60
12x = -60
x = -60/12
x = -5
:
Find y using the 1st equation, replace x with -5
3(-5) + 2y = 5
-15 + 2y = 5
2y = 5 + 15
2y = 20
y = 20/2
y = 10
:
You can check the solution again in the 2nd equation