Question 58561
{{{(x - (2 + i))(x - (2 - i))}}}
= {{{((x - 2) - i)((x - 2) + i))}}}
= {{{(x - 2)^2 - i^2}}}
= {{{(x - 2)^2 - (-1)}}}
= {{{x^2 - 2*x*2 +2^2 + 1}}}
= {{{x^2 - 4*x + 4 + 1}}}
= {{{x^2 - 4*x + 5}}}