Question 636385
Let {{{x}}} is the second number, then the first number is {{{(2/3)x}}}
The equation
{{{(2/3)x+x=10}}}
{{{(5/3)x=10}}}
{{{x=10*3/5}}}
{{{x=6}}} is the second number
{{{(2/3)*6=4}}} is the first number