<PRE><B>Question 636379</B>
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The sum of the logs is the log of the product.  A logarithm is the exponent to which the base is raised to equal the value of the argument.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln(2x)\ =\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ =\ e]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{e}{2}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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