Question 636254
A solution of 61% bleach is to be mixed with a solution of 27% bleach
 to make 68 gallons of a 44% solution.
 How many gallons of each should be used?
:
Let x = amt of 61% bleach required
the resulting mixture is to be 68 gal, therefore:
(68-x) = amt  of 27% solution required
:
A typical mixture equation
:
.61x + .27(68-x) = .44(68)
:
.61x + 18.36 - .27x = 29.92
.61x - .27x = 29.92 - 18.36
.34x = 11.56
x = 11.56/.34
x = 34 gal of 61% solution
and
68 - 34 = 34 gal of 27% solution