Question 636364


      {{{g(x)=(x-9)/(x^2-12x+3)}}}


the domain of {{{g(x)}}} is {{{all}}} real numbers ({{{R}}}) {{{except}}} the roots of denominator {{{x^2-12x+3}}}; as you already know, denominator could NOT be equal to zero. 

To find out what they are, solve using quadratic formula:

*[invoke quadratic_formula 1, -12, 3, "x"]


So, all values of {{{x}}} that are {{{NOT}}} in the domain of {{{g}}} are the solutions 

{{{x=6+sqrt(33)}}} {{{and}}} {{{x=6-sqrt(33)}}}