<PRE><B>Question 636325</B>
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1) *[tex \LARGE f(x)\ =\ 3x^2\ -\ 3x\ +\ 6], evaluate *[tex \LARGE f(-3)]


Just substitute the given value for *[tex \LARGE x] in the definition of your function and then do the arithmetic.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-3)\ =\ 3\left(-3\right)^2\ -\ 3\left(-3\right)\ +\ 6]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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