Question 636312
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Hi,
{{{P=ab^t}}} , where t is the number of months <u>since January 2010</u> (Jan 2010 t = 0, Feb t = 1, etc)
The population of butterflies in a local pasture is 60 in January 2010. a = 60
In March 2010, the population of butterflies is 80:  80 = 60b^2 , {{{b = 2/sqrt(3)}}}
B. According to the model, what will the population of butterflies be in January 2011? t = 12
{{{ P = 60(2/sqrt(3))^12 = 337}}}
 C. According to the model, when will the population reach 200? 
 {{{ 200 = 60 (2/sqrt(3))^t}}}
 {{{200/60 = (2/sqrt(3))^t}}}
  {{{ log(200/60)/log(2/sqrt(3)) = .5229/.0625}}} = t = 8.38 or in the 9th month