Question 636271
The diameters of grapefruits in a certain orchard are normally distributed with a mean of 7.30 inches and a standard deviation of 0.80 inches. 
(A) What percentage of the grapefruits in this orchard have diameters less than 6.7 inches?
z(6.7) = (6.7-7.3)/0.8 = -0.75
P(x < 6.7) = P(z<-0.75) = normalcdf(-100,-0.75) = 0.2266
-------------------------
(B) What percentage of the grapefruits in this orchard are larger than 7.20 inches?
Find the z-score of 7.20
Find the probability z is greater than that z-score.
Ans: 0.5497
===============
Cheers,
Stan H.