Question 636302
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Hi,
Note: {{{A[T] = (1/2)b*h}}}
One leg{{{highlight(y)}}} of a right triangle is <u>7cm shorter than the other leg</u>{{{highlight(x)}}}.
Question states*** area is 30cm^2
  {{{30cm^2 = (1/2)x*y}}}      || {{{ y = (x-7)}}}
      60 = x(x - 7)
    x^2 - 7x - 60 = 0
   (x - 12)(x + 5) = 0   || Tossing out negative solution for unit measure
      x = 12cm   and y = 5cm
Applying the Pythagorean Theorem: {{{sqrt(12^2 + 5^2) = 13cm}}}
P = 12cm + 5cm + 13cm = 30cm