Question 636288
How do i express log base b to number cube root a tothe power -3 times b devided by q power -3 in terms of sums and differences
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logb[a^(-3)*b/q^-3]
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= logb[b*q^3/a^3]
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= logb(b)+3logb(q)-3logb(a)
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= 1 + 3[logb(q/a)]
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Cheers,
Stan H.