Question 636249


{{{v^2-36u^2}}} Start with the given expression.



{{{(v)^2-36u^2}}} Rewrite {{{v^2}}} as {{{(v)^2}}}.



{{{(v)^2-(6u)^2}}} Rewrite {{{36u^2}}} as {{{(6u)^2}}}.



Notice how we have a difference of squares {{{A^2-B^2}}} where in this case {{{A=v}}} and {{{B=6u}}}.



So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{A^2-B^2=(A+B)(A-B)}}} Start with the difference of squares formula.



{{{(v)^2-(6u)^2=(v+6u)(v-6u)}}} Plug in {{{A=v}}} and {{{B=6u}}}.



So this shows us that {{{v^2-36u^2}}} factors to {{{(v+6u)(v-6u)}}}.



In other words {{{v^2-36u^2=(v+6u)(v-6u)}}}.