<PRE><B>Question 636213</B>
(x^2-49)/(2x-1)
Domain: All Real Numbers except x = 1/2
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(x^2-14x+49)/(1-2x) = (x^2-14x+49)/(-(2x-1))
Factor:
(x-7)^2/(1-2x)
Domain: All Real Numbers except x = 1/2
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Least common denominator:
(-(2x-1)
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Dividing:
[(x^2-49)/(2x-1)]/[(x^2-14x+49)/(-(2x-1))]
------
[(x-7)(x+7)/(2x-1)]/[(x-7)^2/(-(2x-1)]
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Invert the denominator and multiply:
[(x-7)(x+7)/(2x-1)]*[(-(2x-1))/(x-7)^2)]
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Cancel factors that are common to a numerator and a denominator:
[(x+7)/1]*[(-1))/(x-7))]
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= -(x+7)/(x-7)
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Cheers,
Stan H.
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