Question 636164
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Distance equals rate times time, so time is equal to distance divided by rate.


The slow plane takes *[tex \LARGE \frac{1500}{r}\ =\ t] hours.


The fast plane takes *[tex \LARGE \frac{2000}{r\ +\ 100}\ =\ t] hours.


Since *[tex \LARGE t] hours is the same as *[tex \LARGE t] hours, we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1500}{r}\ =\ \frac{2000}{r\ +\ 100}]


Cross-multiply and solve for *[tex \LARGE r].  Then calculate *[tex \LARGE r\ +\ 100]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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