Question 361631
i^40
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{{{i = sqrt(-1)}}}
{{{i^2 = -1}}}
{{{i^3 = i^2*i = -i}}}
{{{i^4 = 1}}}
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It's cyclic
i, -1, -i, 1 etc.
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{{{i^40 = (i^4)^10 = 1^10 = 1}}}