Question 636085
Assume the problem is:
 {{{((x+2))/3}}} + {{{((x-1))/4}}} = {{{3/2}}}
multiply by 12 (LCM) to clear the denominators
12*{{{((x+2))/3}}} + 12*{{{((x-1))/4}}} = 12*{{{3/2}}}
Cancel out the denominators
4(x+2) + 3(x-1) = 6(3)
:
4x + 8 + 3x - 3 = 18
7x + 5 = 18
7x = 18 - 5
7x = 13
x = {{{13/7}}}