<PRE><B>Question 636078</B>
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This trinomial is prime over the rationals.  To factor over the reals, set it equal to zero, solve the resulting quadratic equation for the two irrational real roots (call them *[tex \LARGE x_1] and *[tex \LARGE x_2] for purposes of this discussion), and then express your two factors as *[tex \LARGE x\ -\ x_1] and *[tex \LARGE x\ -\ x_2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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