Question 636080
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Use the two-point form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Then rearrange it into slope-intercept form:  *[tex \LARGE y\ =\ mx\ +\ b]


Note that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)]


and a little algebra done on the two-point form after converting it to the point-slope form by substituting *[tex \LARGE m] for *[tex \LARGE \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)], shows that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b\ =\ y_1\ -\ mx_1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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