Question 636066
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
{{{p - 2sqrt(p) - 8 = 0}}}
let x^2 = p
{{{x^2 - 2x - 8 = 0}}}
(x-4)(x+2) = 0
  x = 4  &#8658;   p =  x^2 = 16   and...{{{16 - 8 - 8 = 0}}}
Note: x = -2( p = 4) is an extraneous solution  as  4 -4 - 8 &#8800; 0