Question 635912
factor 25g^6 -10g^3 +1
set equation=0
25g^6 -10g^3 +1=0
let u=g^3
u^2=g^6
..
25u^2-10u+1=0
(5u-1)(5u-1)=0
u=1/5 (multiplicity 2)
u=1/5=g^3
raise both sides to 1/3 power or take cube root of both sides
g=5^(-1/3)
g≈0.5848...
two factors are: irrational number 0.5848...(multiplicity 2)
The other four factors are 2 pairs of non-real or imaginary numbers)