Question 635808
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Hi,
Dealt 6 cards from a 52 card deck  52C6 TOTAL possibilities
P(no spades 'and' 2 7s) = {{{3C2*36C4/(52C6)}}}
P(1Jack and 5 non-jack cards) = {{{4C1*48C5/(52C6)}}}
P(no Jacks) = {{{48C6/(52C6)}}}
P(no more than one Jack) = {{{(48C6 + 4C1*48C5)/(52C6)}}}
P(least 2 Hs and 2 Cs) = 1 - {{{(26C6 + 13C1*13C1*26C4)/(52C6)}}}