Question 635819
Find the coordinates of the vertex for the parabola given by the equation f(x)=-x^2-2x-1
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Do it like this one:
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Find the coordinates of the vertex for the parabola given by the equation 
f(x)=-3x^2-x-1.
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The vertex is on the LOS, Line of Symmetry, or the Axis of Symmetry
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The LOS is x = -b/2a
x = 1/-6 = -1/6
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f(-1/6) = -1/12 + 1/6 - 1 = -11/12
--> vertex (-1/6,-11/12)