Question 58378
Find the maximum of P(x) = -x^2 + 8x + 1.
          In general quadratic fuction F(x)= ax^2 + bx + C is a parabola,       
      we need to find the line of symmetry
        p(x)= -x^2 + 8x + 1 
 Note:(in this case, the graph will open down when the value of A is negative units or sign) A= -1 , b= 8 , c= 1
                          
     the X coordinate of the vertex is given by (-b/2a)= -(+8)/2(-1)= 4
     the y coordinate of the vertex is given by  
     p(-b/2a)or p(4)= -x^2+8x+1
                    = -(4)^2+8(4)+1 
                    = -16 + 32 + 1
                    = 17
     Ans. the maxium of P(X) is 17 
 Note; this kind of problem you can solve by Quadratic fuction Form or Symmetry Form or Factor Form.
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