Question 635589


{{{3x^2+2x-18x-12}}} Start with the given expression



{{{(3x^2+2x)+(-18x-12)}}} Group the terms in two pairs



{{{x(3x+2)-6(3x+2)}}} Factor out the GCF {{{x}}} out of the first group. Factor out the GCF {{{-6}}} out of the second group



{{{(x-6)(3x+2)}}} Since we have the common term {{{3x+2}}}, we can combine like terms



So {{{3x^2+2x-18x-12}}} factors to {{{(x-6)(3x+2)}}}



In other words, {{{3x^2+2x-18x-12=(x-6)(3x+2)}}}