Question 635617

{{{8y^2-10y-3}}}....replace {{{-10y}}} with {{{-12y+2y}}}

{{{8y^2-12y+2y-3}}}...group first two terms and second two terms together

{{{(8y^2-12y)+(2y-3)}}}...factor out {{{4y}}} from {{{(8y^2-12y)}}}

{{{4y(2y-3)+(2y-3)}}}

{{{(2y-3)(4y+1)}}}