Question 635521
{{{ 2sin(2x) + sqrt (3) = 0 }}}
{{{ 2sin(2x) = -sqrt (3) }}}
{{{ sin(2x) = -sqrt(3) / 2 }}}
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The sine is negative in the 3rd and 4th
quadrants. In the 3rd quadrant, the 
angle is {{{ pi + pi/3  = (4*pi)/3 }}} radians or
{{{ 180 + 60 = 240 }}} degrees
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In the 4th quadrant, the angle is 
{{{ 2*pi - pi/3 = (5*pi)/3 }}} radians, or
{{{ 360 - 60 = 300 }}} degrees