Question 635477
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Distance equals rate times time.  So the time the friend drove times his rate of speed is the distance that he drove.  Subtract that distance from 530 miles resulting in the distance still to be driven.  That distance divided by the required time is the average rate of speed required.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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