Question 635403
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Hi,
{{{(x)/(y+1) = 3/2 }}}    || Cross Multiply
  2x = 3(y+1)
   x = {{{(3/2)(y+1) = (3/2)y+ 3/2}}}   and  y = {{{(2/3)x - 1}}}
{{{(x+y)/(x-y) = 7/2}}}    || Cross Multiply
  2(x+y) = 7(x-y)
 2x + 2y = 7x - 7y
      9y = 5x
      {{{ y = (5/9)x  }}}   and {{{x = (9/5)y}}}