Question 635404
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Hi,
x2 + 4y2 + 2x - 24y + 33 = 0
(x+1)^2 + 4(y-3)^2 - 1 - 36 + 33 = 0
(x+1)^2 + 4(y-3)^2 = 4
{{{(x+1)^2/2^2 + (y-3)^2/1^2 = 1}}}
Ellipse:  C(-1,3)
 Standard Form of an Equation of an Ellipse is {{{(x-h)^2/a^2 + (y-k)^2/b^2 = 1 }}} 
where Pt(h,k) is the center. (a variable positioned to correspond with major axis)
 a and b  are the respective vertices distances from center
 and ±{{{sqrt(a^2-b^2)}}}are the foci distances from center: a > b