Question 635275
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Boy are you in for some sticker shock.  $300 is what it costs you for the LAST 10 foot section, but doesn't help you pay for the previous eight 10-foot sections.


Each 10 foot section, and we'll number them from 0 through 8, costs you $100 plus $25 times the number of the section.


So you have *[tex \LARGE 9] sections times $100 plus *[tex \LARGE (0\ *\ 25)\ +\ (1\ *\ 25)\ +\ \cdots\ (8\ *\ 25)], which can be written *[tex \LARGE 25(0\ +\ 1\ +\ 2\ +\ 3\ +\ 4\ +\ 5\ +\ 6\ +\ 7\ +\ 8)].  But the sum of a series of integers can be calculated using:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sum_{i\,=\,0}^8\,a_i\ =\ \frac{(a_0\ +\ a_8)*8}{2}\ =\ \frac{(0\ +\ 8)*8}{2}\ =\ 36]


And so your total is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 900\ +\ (36\ *\ 25)]


Do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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