Question 635219
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Hi,
{{{y = x^2 + 5}}}
Note: the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry
Parabola opens Upward, V(0,5) , y-axis the line of symmetry (x=0) (2,9) &(-2,9)are Pts on this parabola 
Always good idea to sketch any curve
{{{drawing(300,300,   -6, 6, -6, 15,   grid(1),
circle(0, 5,0.3),
circle(2, 9,0.3),
circle(-2, 9,0.3),
graph( 300, 300, -6, 6, -6, 15,0, x^2+5))}}}