Question 635190
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Heron's formula is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ T\ =\ \sqrt{s(s\ -\ a)(s\ -\ b)(s\ -\ c)]


Where did you get the idea that you have to square *[tex \LARGE s(s\ -\ a)(s\ -\ b)(s\ -\ c)], since *[tex \LARGE \sqrt{x}] means take the square root?


Just multiply it out and then take the square root.  You have 5 factors of 3, which you can write as 81 times 3.  The square root of 81 is 9 and the square root of 3 is *[tex \LARGE \sqrt{3}].  Don't forget to double your answer since it takes two of these triangles to make your rhombus.  And oh by the way, "the little house thing" is called a radical.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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