Question 634790
A car traveling at a constant speed of 98km/h on a freeway passes a sign that
 states that the next town is 80km away.
:
a) A second car passes the sign 10 minutes after the first car.
 If it was traveling at 105km/h, find a model for its distance from the town
:
Find how far behind the 2nd car is behind the first when it passes the sign
Then how far it is from the town at that time
Convert 10 min to 1/6 hr
105*{{{1/6}}} = 17.5 km, so it is 17.5+80 = 97.5 km from the town
let t = travel time of the 2nd car
d(t) = 97.5 - 105t; an equation for the distance the 2nd car is from town
:
:
b) What time did the second car pass through the town if the first car
 passed the sign at 12 noon?
Find the travel time of 2nd car: 97.5/105 = .92857 * 60 = 55.7 min
Find the travel time of 1st car: 80/98 = .8889 * 60 = 53.3 min
55.7 - 53.3 = 2.4 min
If Car 1 arrives at noon, car 2 arrives 2.4 min after noon