<PRE><B>Question 58274</B>
How many ounces of pure gold must be added to five ounces of something that is 1% gold in order that the mixture is 6% gold?
:
Let x = amt of pure gold required
:
Write a per cent gold equation. (100% gold is 1.0(x))
The final amt will be be (x+5)
:
.01(5) + 1.0(x) = .06(x+5)
.05 + 1x = .06x + .3
1x - .06x = .3 - .05
.94x = .25
x = .266 oz of pure gold required
:
Check:
.05 + .266 = .06(5.266)
.05 + .266 = .316, checks out </PRE>