Question 634752
If csc t = 25/24 and tan t < 0, then sec t is equal to what?
assume domain [0, 2&#960;]
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Since tan<0, and csc>0, you are working with a reference angle in quadrant II
csc=hypotenuse/opp side=25/24
adj side=&#8730;(25^2-24^2)=&#8730;49=7
sec t=hypotenuse/adj side=-25/7 in quadrant II