Question 634728
Which of the following quadratic equations has solutions x=6a and x=-3b?
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Modify:
x-6a = 0
x+3b = 0
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Multiply:
x^2 -6ax+3bx-18ab = 0
Rearrange:
x^2 -x(6a-3b)-18ab = 0
x^2+x(3b-6a)-18ab = 0
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Ans D
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Cheers,
Stan H.
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A. x^2-18ab=0
B. x^2-x(3b-6a)-18ab=0
C. x^2-x(3b+6a)+18ab=0
D. x^2+x(3b-6a)-18ab=0
E. x^2+x(3b+6a)+18ab=0