Question 634686
# 1


Let d = common difference


So 


6+d is the next term (after 6)


6+d+d = 6+2d is the next term (after the previous term above)


6+d+d+d = 6+3d is the next term (after the previous term above)


6+d+d+d+d = 6+4d is the next term (after the previous term above)


6+d+d+d+d+d = 6+5d is the next term (after the previous term above)


So we have the sequence...


6, 6+d, 6+2d, 6+3d, 6+4d, 6+5d


We have 6 terms and 4 terms are sandwiched between the terms "6" and "6+5d"


So the term 6+5d must be the term 121. So 6+5d = 121


Solve this for d. Then use this solution to find the missing 4 terms.


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# 2


Let r = common ratio


So 


We start off with 6


Then we move to 6*r or 6r to get the next term


Then we multiply by r again to get 6r^2 as the next term


Then we repeat to get 6r^3


Repeat again to get 6r^4


So we have the 5 terms


6, 6r, 6r^2, 6r^3, 6r^4


There are 3 terms in between the first term 6 and the last term 6r^4. The last term given to us is 3.9366


So 


6r^4 = 3.9366


Solve this equation for r. Then use it to find the missing terms.