Question 634651
I'll do the first one to get you started.


Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-3,-7\right)]. So this means that {{{x[1]=-3}}} and {{{y[1]=-7}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(9,-7\right)].  So this means that {{{x[2]=9}}} and {{{y[2]=-7}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-7--7)/(9--3)}}} Plug in {{{y[2]=-7}}}, {{{y[1]=-7}}}, {{{x[2]=9}}}, and {{{x[1]=-3}}}



{{{m=(0)/(9--3)}}} Subtract {{{-7}}} from {{{-7}}} to get {{{0}}}



{{{m=(0)/(12)}}} Subtract {{{-3}}} from {{{9}}} to get {{{12}}}



{{{m=0}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-3,-7\right)] and *[Tex \LARGE \left(9,-7\right)] is {{{m=0}}}