<PRE><B>Question 634591</B>
A cage has 10 male and 5 female birds. If three birds are selected at random from the cage , what is the probability that all are males?
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# of ways to succeed: 10C3 = (10*9*8)/(1*2*3) = 120 ways
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# of possible outcomes: 15C3 = (15*14*13)/(1*2*3) = 455
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P(3 males) = 120/455
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Cheers,
Stan H.
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