Question 634580
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
log(base x)(5 + 3x - x^2) = 2
 my solution: 
x^2 = 5 + 3x - x^2
 x^2 + x^2 = 5 + 3x
 2x^2 = 5 + 3x
 2x^2 - 5 - 3x = 0
 2x^2 + 2x - 5x - 5 = 0
 2x(x + 1) - 5(x + 1) = 0
 (2x - 5)(x + 1) = 0    Yes.  Good work!
Following thru to the finish...
  x = 5/4  OR x = {{{highlight(-1)}}}     
Note: {{{2x^2-3x-5 = 0}}} and {{{2(-1)^2 - 3(-1) - 5 = 0}}}
Always a good idea to check answers found,when it is possible to do so