Question 634485
{{{t=-62.5*ln(1-n/80)}}}To solve for "n", we need to "peel away" the rest of the right side of the equation. First isolate the log by dividing by 62.5:
{{{t/62.5=ln(1-n/80)}}}
To eliminate a log, rewrite the equation in exponential form. In general {{{log(a, (p)) = q}}} is equivalent to {{{p = a^q}}}. Using this pattern (and the fact that the base of ln is "e") we get:
{{{e^((t/62.5))=1-n/80}}}
Subtracting 1 from each side:
{{{e^((t/62.5))-1= -n/80}}}
Multiplying each side by -80:
{{{-80e^((t/62.5))-1= n}}}