Question 634452
{{{2x^2-7x+6=0}}}
<p>One of the ways to solve this is to use the quadratic equation. But first, we must identify the a, b, and c values.
<p>A is 2 (because the prerequisite for the first variable to make it a quadratic equation is x^2)
<p>B is -7 (because the prerequisite for the second variable to make it a quadratic equation is x)
<p>C is 6 (because there is no prerequisite for the third variable to make it a quadratic equation)
<p>)(NOTE: A could be x^3 and B could be x^2. All that is required is that it goes from one level of exponents to the next. Squared to a normal x to no x, or maybe Cubed to squared to normal x)

<p>Now we can solve the problem with the quadratic equation.
<p>*[invoke solve_quadratic_equation 2, -7, 6]