<PRE><B>Question 634383</B>
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Sorry, using the remainder theorem requires &lt;b&gt;&lt;i&gt;both&lt;/i&gt;&lt;/b&gt; a polynomial function &lt;b&gt;&lt;i&gt;and&lt;/i&gt;&lt;/b&gt; a divisor, in other words a particular value for &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt;


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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