Question 633993
Let x be the smaller and y be the larger integer.


The Larger of 2 integers is 4 times the smaller.
y=4x..........(1)
The sum of the 2 integers is less than twenty
x+y<20
Put the value of y from (1) to above equation
x+4x<20
5x<20
5x/5<20/5
x<4
so x is 3,2 or 1
Put the these values of x in (1)
y=4(3)
y=12
y=4(2)
y=8
y=4(1)
y=4

So when x = 3,2,1
        y = 12,8,4

Largest possible values (x,y)=(3,12)