Question 633931
Give the domain for g(x) = √(x-4)^2-1. Explain/show your reasoning.
(The whole (x-4)^2-1 part is "under" the squareroot symbol)
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The rule that applies here is that a radican≥0 (what is under the square root symbol)
(x-4)^2-1≥0
this is a difference of 2 squares
(x-4+1(x-4-1)≥0
(x-3)(x-5)≤0
number line
<....+....3.....-......5....+......>
Domain: (-&#8734;,3] U [5,&#8734;)