Question 633951
x1		y1	x2	y2									
8		-6	4	-2									
													
slope m =		(y2-y1)/(x2-x1)											
(	-2	-	-6	)/(	4	-	8	)					
(	4	/	-4	)  									
m=		-1    						 					
The required line passes through both the points. So we select one point and plug it with the slope 													
Plug value of  the slope  and point	(8,-6) in						
Y	=	m	x	+	b								
-6.00	=	-1    	*	8	+	b							
-6.00	=	-8    	+	b									
b=	-6    	+	2    										
b=	-8      												
So the equation  will be													
Y 	=	-x+2    								
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