Question 633964
6 & -2/3 are the roots of the equation

Let the roots be  {{{alpha}}} & {{{beta}}}

in the general equation {{{ax^2+bx+c=0 }}}

sum of the roots = -16/3 = -b/a

product of roots = -4  c/a

{{{x^2+(-16/3)x-4=0}}}

{{{3x^2-16x-12=0}}}