Question 633892
Find three consecutive odd numbers such that the square of the second number is 192 less than the square of the third number. 
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
(2x+1)^2 = (2x+3)^2-192
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4x^2+4x+1 = 4x^2+12x+9 - 192
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-8x = -184
x = 23
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1st: 2x-1 = 2*23-1 = 45
2nd: 47
3rd: 49
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Cheers,
Stan H.